What are the solutions to the equation -2a^2-11a-10=0 ?

The solutions to the equation -2a^2-11a-10=0 are a=-(11+sqrt(41))/4 ,a=-(11-sqrt(41))/4

Find the zeros of -2a^2-11a-10=0

The zeros of -2a^2-11a-10=0 are a=-(11+sqrt(41))/4 ,a=-(11-sqrt(41))/4

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- 2 a^{2} - 11 a - 10 = 0

a = - \frac{11 + 41}{4}, a = - \frac{11 - 41}{4}

Decimal Notation

a = - 4.35078 \dots, a = - 1.14921 \dots

Solution steps

- 2 a^{2} - 11 a - 10 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 ( - 2 ) ( - 10 )}{2 ( - 2 )}

(- 11)^{2} - 4 (- 2) (- 10) = 41

a_{1, 2} = \frac{- ( - 11 ) \pm 41}{2 ( - 2 )}

Separate the solutions

a_{1} = \frac{- ( - 11 ) + 41}{2 ( - 2 )}, a_{2} = \frac{- ( - 11 ) - 41}{2 ( - 2 )}

a = \frac{- ( - 11 ) + 41}{2 ( - 2 )} : - \frac{11 + 41}{4}

a = \frac{- ( - 11 ) - 41}{2 ( - 2 )} : - \frac{11 - 41}{4}

The solutions to the quadratic equation are:

a = - \frac{11 + 41}{4}, a = - \frac{11 - 41}{4}

\frac{x}{2} - \frac{x}{3} + \frac{x}{5} = \frac{11}{6}

\frac{1}{2} (6 x - 10) = 7

x^{6} + 4 x^{3} + 3

- 0.5244 = \frac{x - 47}{14}

49 x^{2} - 16 = 0

What are the solutions to the equation -2a^2-11a-10=0 ?
The solutions to the equation -2a^2-11a-10=0 are a=-(11+sqrt(41))/4 ,a=-(11-sqrt(41))/4
Find the zeros of -2a^2-11a-10=0
The zeros of -2a^2-11a-10=0 are a=-(11+sqrt(41))/4 ,a=-(11-sqrt(41))/4