What are the solutions to the equation 2x=9-x^2 ?

The solutions to the equation 2x=9-x^2 are x=-1-sqrt(10),x=sqrt(10)-1

Find the zeros of 2x=9-x^2

The zeros of 2x=9-x^2 are x=-1-sqrt(10),x=sqrt(10)-1

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2 x = 9 - x^{2}

x = - 1 - 10, x = 10 - 1

Solution steps

2 x = 9 - x^{2}

Switch sides

9 - x^{2} = 2 x

Move

2 x

to the left side

9 - x^{2} - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 2 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 9}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 9 = 210

x_{1, 2} = \frac{- ( - 2 ) \pm 2 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 10}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 2 10}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 2 10}{2 ( - 1 )} : - 1 - 10

x = \frac{- ( - 2 ) - 2 10}{2 ( - 1 )} : 10 - 1

The solutions to the quadratic equation are:

x = - 1 - 10, x = 10 - 1

882 = - 13.957 x^{2} + 310.63 x + 31.971

x y^{2} - y^{3}

a^{2} = 400

4 \geq 4 v - 4

3 x^{2} + 36 x + 81 = 0

What are the solutions to the equation 2x=9-x^2 ?
The solutions to the equation 2x=9-x^2 are x=-1-sqrt(10),x=sqrt(10)-1
Find the zeros of 2x=9-x^2
The zeros of 2x=9-x^2 are x=-1-sqrt(10),x=sqrt(10)-1