What are the solutions to the equation (x+5)(x-5)=0 ?

The solutions to the equation (x+5)(x-5)=0 are x=-5,x=5

Find the zeros of (x+5)(x-5)=0

The zeros of (x+5)(x-5)=0 are x=-5,x=5

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(x + 5) (x - 5) = 0

x = - 5, x = 5

Solution steps

(x + 5) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 5 = 0 or x - 5 = 0

Solve

x + 5 = 0 : x = - 5

Solve

x - 5 = 0 : x = 5

The solutions to the quadratic equation are:

x = - 5, x = 5

(4 + 7 i)^{2}

(x^{5} y^{2}) (x^{- 6} y)

1.1 5^{2} + (- 3.43)^{2}

\frac{5}{3} (2 - x) \geq \frac{2}{3} (3 - 5 x)

- \frac{1}{2} (2 x + 1) \leq - \frac{3}{8} (x + 2)

What are the solutions to the equation (x+5)(x-5)=0 ?
The solutions to the equation (x+5)(x-5)=0 are x=-5,x=5
Find the zeros of (x+5)(x-5)=0
The zeros of (x+5)(x-5)=0 are x=-5,x=5