What are the solutions to the equation 7x^2+5x-2=0 ?

The solutions to the equation 7x^2+5x-2=0 are x= 2/7 ,x=-1

Find the zeros of 7x^2+5x-2=0

The zeros of 7x^2+5x-2=0 are x= 2/7 ,x=-1

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7 x^{2} + 5 x - 2 = 0

x = \frac{2}{7}, x = - 1

Decimal Notation

x = 0.28571 \dots, x = - 1

Solution steps

7 x^{2} + 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 7 ( - 2 )}{2 \cdot 7}

5^{2} - 4 \cdot 7 (- 2) = 9

x_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 5 + 9}{2 \cdot 7}, x_{2} = \frac{- 5 - 9}{2 \cdot 7}

x = \frac{- 5 + 9}{2 \cdot 7} : \frac{2}{7}

x = \frac{- 5 - 9}{2 \cdot 7} : - 1

The solutions to the quadratic equation are:

x = \frac{2}{7}, x = - 1

(\frac{n}{5} - \frac{5}{n})^{2}

\frac{5}{3} (2 x + 2) - 10 \geq 2 x + 2 (\frac{2}{3} x + 2)

\frac{\frac{1}{2}}{5}

x^{2} y^{5} + y^{3}

4 c < 8

What are the solutions to the equation 7x^2+5x-2=0 ?
The solutions to the equation 7x^2+5x-2=0 are x= 2/7 ,x=-1
Find the zeros of 7x^2+5x-2=0
The zeros of 7x^2+5x-2=0 are x= 2/7 ,x=-1