What are the solutions to the equation 10x-x^2=21 ?

The solutions to the equation 10x-x^2=21 are x=3,x=7

Find the zeros of 10x-x^2=21

The zeros of 10x-x^2=21 are x=3,x=7

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10 x - x^{2} = 21

x = 3, x = 7

Solution steps

10 x - x^{2} = 21

Move

21

to the left side

10 x - x^{2} - 21 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 10 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) ( - 21 )}{2 ( - 1 )}

1 0^{2} - 4 (- 1) (- 21) = 4

x_{1, 2} = \frac{- 10 \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 10 + 4}{2 ( - 1 )}, x_{2} = \frac{- 10 - 4}{2 ( - 1 )}

x = \frac{- 10 + 4}{2 ( - 1 )} : 3

x = \frac{- 10 - 4}{2 ( - 1 )} : 7

The solutions to the quadratic equation are:

x = 3, x = 7

a c + a x + b c + b x

(2 x^{4} y^{2})^{3}

- x^{3} + 5 x^{2} - 8 x + 4

256 x^{4} - 81

11 x^{2} - 26 x - 61 = 0

What are the solutions to the equation 10x-x^2=21 ?
The solutions to the equation 10x-x^2=21 are x=3,x=7
Find the zeros of 10x-x^2=21
The zeros of 10x-x^2=21 are x=3,x=7