What is ((2x^3y^{-2})^2)/(x^{-2)y^3} ?

The solution to ((2x^3y^{-2})^2)/(x^{-2)y^3} is (4x^8)/(y^7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((2x^3y^{-2})^2)/(x^{-2)y^3}

simplify

\frac{( 2 x ^{3} y ^{- 2} ) ^{2}}{x ^{- 2} y ^{3}}

\frac{4 x ^{8}}{y ^{7}}

Solution steps

\frac{( 2 x ^{3} y ^{- 2} ) ^{2}}{x ^{- 2} y ^{3}}

Simplify

(2 x^{3} y^{- 2})^{2} : \frac{4 x ^{6}}{y ^{4}}

= \frac{\frac{4 x ^{6}}{y ^{4}}}{x ^{- 2} y ^{3}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{4 x ^{6}}{y ^{4} x ^{- 2} y ^{3}}

Simplify

\frac{x ^{6}}{x ^{- 2}} : x^{8}

= \frac{4 x ^{8}}{y ^{4} y ^{3}}

Simplify

y^{4} y^{3} : y^{7}

= \frac{4 x ^{8}}{y ^{7}}

12 = n - 9

5 x^{\frac{1}{2}} \cdot 5 x^{\frac{1}{2}}

9 b^{3} + 3 b^{2} + 24 b + 8

i^{18}

\frac{x ^{5} y ^{2} z ^{8}}{( x y ) ^{- 3}}

What is ((2x^3y^{-2})^2)/(x^{-2)y^3} ?
The solution to ((2x^3y^{-2})^2)/(x^{-2)y^3} is (4x^8)/(y^7)