What are the solutions to the equation 6+(2x+4)/3 x=8 ?

The solutions to the equation 6+(2x+4)/3 x=8 are x=1,x=-3

Find the zeros of 6+(2x+4)/3 x=8

The zeros of 6+(2x+4)/3 x=8 are x=1,x=-3

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6 + \frac{2 x + 4}{3} x = 8

x = 1, x = - 3

Solution steps

6 + \frac{2 x + 4}{3} x = 8

Multiply both sides by

3

18 + x (2 x + 4) = 24

Expand

18 + x (2 x + 4) : 18 + 2 x^{2} + 4 x

18 + 2 x^{2} + 4 x = 24

Move

24

to the left side

2 x^{2} + 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 6) = 8

x_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 8}{2 \cdot 2}, x_{2} = \frac{- 4 - 8}{2 \cdot 2}

x = \frac{- 4 + 8}{2 \cdot 2} : 1

x = \frac{- 4 - 8}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

2 z^{2} + 13 z + 11

356

1^{\frac{1}{4}}

10 x^{2} - 21 x + 2 = 0

- 5 x^{2} - 8 x = 15

What are the solutions to the equation 6+(2x+4)/3 x=8 ?
The solutions to the equation 6+(2x+4)/3 x=8 are x=1,x=-3
Find the zeros of 6+(2x+4)/3 x=8
The zeros of 6+(2x+4)/3 x=8 are x=1,x=-3