What are the solutions to the equation (x-2)(x+7)=0 ?

The solutions to the equation (x-2)(x+7)=0 are x=2,x=-7

Find the zeros of (x-2)(x+7)=0

The zeros of (x-2)(x+7)=0 are x=2,x=-7

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(x - 2) (x + 7) = 0

x = 2, x = - 7

Solution steps

(x - 2) (x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 7 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 7 = 0 : x = - 7

The solutions to the quadratic equation are:

x = 2, x = - 7

5 x - 8 < 17

3 (5 y + 1) = 18 y

- 7 s - 4 s = - 19

(1 6^{2})^{\frac{1}{4}}

\frac{5 π}{12} + 2 π

What are the solutions to the equation (x-2)(x+7)=0 ?
The solutions to the equation (x-2)(x+7)=0 are x=2,x=-7
Find the zeros of (x-2)(x+7)=0
The zeros of (x-2)(x+7)=0 are x=2,x=-7