What are the solutions to the equation 3m^2+7m=2 ?

The solutions to the equation 3m^2+7m=2 are m=(-7+sqrt(73))/6 ,m=(-7-sqrt(73))/6

Find the zeros of 3m^2+7m=2

The zeros of 3m^2+7m=2 are m=(-7+sqrt(73))/6 ,m=(-7-sqrt(73))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 m^{2} + 7 m = 2

m = \frac{- 7 + 73}{6}, m = \frac{- 7 - 73}{6}

Decimal Notation

m = 0.25733 \dots, m = - 2.59066 \dots

Solution steps

3 m^{2} + 7 m = 2

Move

2

to the left side

3 m^{2} + 7 m - 2 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 2) = 73

m_{1, 2} = \frac{- 7 \pm 73}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- 7 + 73}{2 \cdot 3}, m_{2} = \frac{- 7 - 73}{2 \cdot 3}

m = \frac{- 7 + 73}{2 \cdot 3} : \frac{- 7 + 73}{6}

m = \frac{- 7 - 73}{2 \cdot 3} : \frac{- 7 - 73}{6}

The solutions to the quadratic equation are:

m = \frac{- 7 + 73}{6}, m = \frac{- 7 - 73}{6}

15 a^{2} b - 10 a b^{2}

e^{5 l n (5)}

\frac{3 - 1}{1 + 3}

t^{2} - 2 t = 7

\frac{4.1}{4.1 - 4}

What are the solutions to the equation 3m^2+7m=2 ?
The solutions to the equation 3m^2+7m=2 are m=(-7+sqrt(73))/6 ,m=(-7-sqrt(73))/6
Find the zeros of 3m^2+7m=2
The zeros of 3m^2+7m=2 are m=(-7+sqrt(73))/6 ,m=(-7-sqrt(73))/6