What are the solutions to the equation -54x^2+672x=0 ?

The solutions to the equation -54x^2+672x=0 are x=0,x= 112/9

Find the zeros of -54x^2+672x=0

The zeros of -54x^2+672x=0 are x=0,x= 112/9

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- 54 x^{2} + 672 x = 0

x = 0, x = \frac{112}{9}

Decimal Notation

x = 0, x = 12.44444 \dots

Solution steps

- 54 x^{2} + 672 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 672 \pm 67 2 ^{2} - 4 ( - 54 ) \cdot 0}{2 ( - 54 )}

67 2^{2} - 4 (- 54) \cdot 0 = 672

x_{1, 2} = \frac{- 672 \pm 672}{2 ( - 54 )}

Separate the solutions

x_{1} = \frac{- 672 + 672}{2 ( - 54 )}, x_{2} = \frac{- 672 - 672}{2 ( - 54 )}

x = \frac{- 672 + 672}{2 ( - 54 )} : 0

x = \frac{- 672 - 672}{2 ( - 54 )} : \frac{112}{9}

The solutions to the quadratic equation are:

x = 0, x = \frac{112}{9}

2 x^{2} + 3 x - 5 > 0

\frac{16 2}{2 12}

(2 - \frac{1}{2})^{2}

- 2 (3 x - 3) = - 30

\frac{x + 1}{6} + \frac{x - 3}{3} = \frac{5}{6}

What are the solutions to the equation -54x^2+672x=0 ?
The solutions to the equation -54x^2+672x=0 are x=0,x= 112/9
Find the zeros of -54x^2+672x=0
The zeros of -54x^2+672x=0 are x=0,x= 112/9