What is (4/7 m)^2(49m)(17p)(1/34 p^5) ?

The solution to (4/7 m)^2(49m)(17p)(1/34 p^5) is 8m^3p^6

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simplify (4/7 m)^2(49m)(17p)(1/34 p^5)

simplify

(\frac{4}{7} m)^{2} (49 m) (17 p) (\frac{1}{34} p^{5})

8 m^{3} p^{6}

Solution steps

(\frac{4}{7} m)^{2} (49 m) (17 p) (\frac{1}{34} p^{5})

Simplify

(\frac{4}{7} m)^{2} : \frac{16 m ^{2}}{49}

= \frac{16 m ^{2}}{49} \cdot 49 m \cdot 17 p \frac{1}{34} p^{5}

Multiply the numbers:

49 \cdot 17 = 833

= \frac{16 m ^{2}}{49} \cdot 833 m p \frac{1}{34} p^{5}

Simplify

p p^{5} : p^{6}

= \frac{16 m ^{2}}{49} \cdot 833 m p^{6} \frac{1}{34}

= \frac{1}{34} \cdot 833 m p^{6} \frac{16 m ^{2}}{49}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{1 \cdot 833 m p ^{6} \cdot 16 m ^{2}}{34 \cdot 49}

Multiply the numbers:

1 \cdot 833 \cdot 16 = 13328

= \frac{13328 m p ^{6} m ^{2}}{34 \cdot 49}

Factor the number:

13328 = 34 \cdot 392

= \frac{34 \cdot 392 m p ^{6} m ^{2}}{34 \cdot 49}

Cancel the common factor:

34

= \frac{392 m p ^{6} m ^{2}}{49}

Divide the numbers:

\frac{392}{49} = 8

= 8 m p^{6} m^{2}

Simplify

m m^{2} : m^{3}

= 8 m^{3} p^{6}

4 n - 1 = 6 n + 8 - 8 n + 15

6 - 2 j = - 3 j

(- \frac{a}{b})^{4}

x^{2} - 6 x + 9 = x^{2} - 9

(108 - 63)^{2}

What is (4/7 m)^2(49m)(17p)(1/34 p^5) ?
The solution to (4/7 m)^2(49m)(17p)(1/34 p^5) is 8m^3p^6