What are the solutions to the equation x^2-8x-10=0 ?

The solutions to the equation x^2-8x-10=0 are x=4+sqrt(26),x=4-sqrt(26)

Find the zeros of x^2-8x-10=0

The zeros of x^2-8x-10=0 are x=4+sqrt(26),x=4-sqrt(26)

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x^{2} - 8 x - 10 = 0

x = 4 + 26, x = 4 - 26

Decimal Notation

x = 9.09901 \dots, x = - 1.09901 \dots

Solution steps

x^{2} - 8 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 10) = 226

x_{1, 2} = \frac{- ( - 8 ) \pm 2 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 26}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 26}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 26}{2 \cdot 1} : 4 + 26

x = \frac{- ( - 8 ) - 2 26}{2 \cdot 1} : 4 - 26

The solutions to the quadratic equation are:

x = 4 + 26, x = 4 - 26

14 n^{3} + 7 n + 7 n^{2}

- 2 m \leq 8

x^{3} + 6 x^{2} - x - 6

- 8 < 3 x - 9 < 15

\frac{( - a - b ) ^{2}}{a + b}

What are the solutions to the equation x^2-8x-10=0 ?
The solutions to the equation x^2-8x-10=0 are x=4+sqrt(26),x=4-sqrt(26)
Find the zeros of x^2-8x-10=0
The zeros of x^2-8x-10=0 are x=4+sqrt(26),x=4-sqrt(26)