What are the solutions to the equation 4x^2-16x-48=0 ?

The solutions to the equation 4x^2-16x-48=0 are x=6,x=-2

Find the zeros of 4x^2-16x-48=0

The zeros of 4x^2-16x-48=0 are x=6,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 16 x - 48 = 0

x = 6, x = - 2

Solution steps

4 x^{2} - 16 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 ( - 48 )}{2 \cdot 4}

(- 16)^{2} - 4 \cdot 4 (- 48) = 32

x_{1, 2} = \frac{- ( - 16 ) \pm 32}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 32}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 32}{2 \cdot 4}

x = \frac{- ( - 16 ) + 32}{2 \cdot 4} : 6

x = \frac{- ( - 16 ) - 32}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

x = 6, x = - 2

(2 y^{2})^{2} \times (- 3 y^{2})^{2}

(x y^{2} z^{3})^{- 1} (x yz)^{3}

(\frac{5}{9})^{- 2}

5 + \frac{1}{7} b = - 2

275

What are the solutions to the equation 4x^2-16x-48=0 ?
The solutions to the equation 4x^2-16x-48=0 are x=6,x=-2
Find the zeros of 4x^2-16x-48=0
The zeros of 4x^2-16x-48=0 are x=6,x=-2