What are the solutions to the equation x^2+4x-20=0 ?

The solutions to the equation x^2+4x-20=0 are x=2(sqrt(6)-1),x=-2(1+sqrt(6))

Find the zeros of x^2+4x-20=0

The zeros of x^2+4x-20=0 are x=2(sqrt(6)-1),x=-2(1+sqrt(6))

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x^{2} + 4 x - 20 = 0

x = 2 (6 - 1), x = - 2 (1 + 6)

Decimal Notation

x = 2.89897 \dots, x = - 6.89897 \dots

Solution steps

x^{2} + 4 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 20) = 46

x_{1, 2} = \frac{- 4 \pm 4 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 6}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 6}{2 \cdot 1}

x = \frac{- 4 + 4 6}{2 \cdot 1} : 2 (6 - 1)

x = \frac{- 4 - 4 6}{2 \cdot 1} : - 2 (1 + 6)

The solutions to the quadratic equation are:

x = 2 (6 - 1), x = - 2 (1 + 6)

16 + 16 x + 3 x^{2}

3 x - 5 = 7 \cdot (x - 3)

\frac{( m + 7 )}{7} + \frac{( m + 7 )}{5}

x + \frac{5}{6} = 2 x - \frac{5}{6}

\frac{3 - 2 i}{3 + 2 i}

What are the solutions to the equation x^2+4x-20=0 ?
The solutions to the equation x^2+4x-20=0 are x=2(sqrt(6)-1),x=-2(1+sqrt(6))
Find the zeros of x^2+4x-20=0
The zeros of x^2+4x-20=0 are x=2(sqrt(6)-1),x=-2(1+sqrt(6))