What are the solutions to the equation t^2+11t+30=0 ?

The solutions to the equation t^2+11t+30=0 are t=-5,t=-6

Find the zeros of t^2+11t+30=0

The zeros of t^2+11t+30=0 are t=-5,t=-6

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t^{2} + 11 t + 30 = 0

t = - 5, t = - 6

Solution steps

t^{2} + 11 t + 30 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 30}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 30 = 1

t_{1, 2} = \frac{- 11 \pm 1}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 11 + 1}{2 \cdot 1}, t_{2} = \frac{- 11 - 1}{2 \cdot 1}

t = \frac{- 11 + 1}{2 \cdot 1} : - 5

t = \frac{- 11 - 1}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

t = - 5, t = - 6

0.18 (200 - x) + 0.1 x = 216

- (\frac{7}{9})^{0}

22 \cdot 32

\frac{y ^{6}}{y ^{2}}

4 x - 5 = 2 - x

What are the solutions to the equation t^2+11t+30=0 ?
The solutions to the equation t^2+11t+30=0 are t=-5,t=-6
Find the zeros of t^2+11t+30=0
The zeros of t^2+11t+30=0 are t=-5,t=-6