What are the solutions to the equation (r-4)2(r+8)=0 ?

The solutions to the equation (r-4)2(r+8)=0 are r=4,r=-8

Find the zeros of (r-4)2(r+8)=0

The zeros of (r-4)2(r+8)=0 are r=4,r=-8

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(r - 4) 2 (r + 8) = 0

r = 4, r = - 8

Solution steps

(r - 4) \cdot 2 (r + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r - 4 = 0 or r + 8 = 0

Solve

r - 4 = 0 : r = 4

Solve

r + 8 = 0 : r = - 8

The solutions to the quadratic equation are:

r = 4, r = - 8

\frac{- 4}{9} + \frac{- 11}{90} + \frac{101}{900} + \frac{8720}{9000}

\frac{20 !}{2 ! 18 !}

4 \times \frac{3}{4}

2 x^{2} + 4 x + 2

150 - 26

What are the solutions to the equation (r-4)2(r+8)=0 ?
The solutions to the equation (r-4)2(r+8)=0 are r=4,r=-8
Find the zeros of (r-4)2(r+8)=0
The zeros of (r-4)2(r+8)=0 are r=4,r=-8