What is |sqrt(pi)-x|>=-5 ?

The solution to |sqrt(pi)-x|>=-5 is True for all x

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|sqrt(pi)-x|>=-5

π - x \geq - 5

True for all x

Interval Notation

(- \infty, \infty)

Solution steps

π - x \geq - 5

Absolute values are always greater or equal to 0

True for all x

2 x + 4 > 10

- 3245

1 - 6

\frac{\frac{a}{b}}{c}

36 x^{2} + 60 x + 25