What are the solutions to the equation a^2+1.5^2=0.5^2 ?

The solutions to the equation a^2+1.5^2=0.5^2 are a=sqrt(2)i,a=-sqrt(2)i

Find the zeros of a^2+1.5^2=0.5^2

The zeros of a^2+1.5^2=0.5^2 are a=sqrt(2)i,a=-sqrt(2)i

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a^{2} + 1. 5^{2} = 0. 5^{2}

a = 2 i, a = - 2 i

Solution steps

a^{2} + 1. 5^{2} = 0. 5^{2}

Move

1. 5^{2}

to the right side

a^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = - 2, a = - - 2

- 2 = 2 i

- - 2 = - 2 i

a = 2 i, a = - 2 i

7 \leq \frac{x + 2}{4}

\frac{x ^{2} ( 5 + x ) ( x - 7 )}{( x + 2 ) ( x - 4 )} \geq 0

10 f + 2 \geq 6 f + 7

(\frac{3}{5}) x = 6 x - 18

14 a + 21 a^{2} + 21 a^{3}

What are the solutions to the equation a^2+1.5^2=0.5^2 ?
The solutions to the equation a^2+1.5^2=0.5^2 are a=sqrt(2)i,a=-sqrt(2)i
Find the zeros of a^2+1.5^2=0.5^2
The zeros of a^2+1.5^2=0.5^2 are a=sqrt(2)i,a=-sqrt(2)i