What is (34i)/(1-4i) ?

The solution to (34i)/(1-4i) is -8+2i

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simplify (34i)/(1-4i)

simplify

\frac{34 i}{1 - 4 i}

- 8 + 2 i

Solution steps

\frac{34 i}{1 - 4 i}

Multiply by the conjugate

\frac{1 + 4 i}{1 + 4 i}

= \frac{34 i ( 1 + 4 i )}{( 1 - 4 i ) ( 1 + 4 i )}

Simplify

\frac{34 i ( 1 + 4 i )}{( 1 - 4 i ) ( 1 + 4 i )} : \frac{34 i - 136}{17}

= \frac{34 i - 136}{17}

Rewrite in standard complex form:

- 8 + 2 i

= - 8 + 2 i

96 c^{4} d^{2}

\frac{9 a ^{2} + 3 a}{3 a}

\frac{1}{2} (6 k + 10) + 5 k

4 h + 5 = 106

44 = 11 y + 55