What is (6x+2)(x-1)<= (2x-3)(3x-2) ?

The solution to (6x+2)(x-1)<= (2x-3)(3x-2) is x<= 8/9

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(6x+2)(x-1)<= (2x-3)(3x-2)

(6 x + 2) (x - 1) \leq (2 x - 3) (3 x - 2)

x \leq \frac{8}{9}

Interval Notation

(- \infty, \frac{8}{9}]

Decimal Notation

x \leq 0.88888 \dots

Solution steps

(6 x + 2) (x - 1) \leq (2 x - 3) (3 x - 2)

Rewrite in standard form

9 x - 8 \leq 0

Move

8

to the right side

9 x \leq 8

Divide both sides by

9

x \leq \frac{8}{9}

3 (1 - 9 a) + 22 a = 2 (2 a - 9) - 15

x^{2} + 2 x + 2 = 0

25 x^{2} + 70 x + 49

\frac{6 ^{8}}{6 ^{10}}

\frac{2}{3} y = 20

What is (6x+2)(x-1)<= (2x-3)(3x-2) ?
The solution to (6x+2)(x-1)<= (2x-3)(3x-2) is x<= 8/9