What are the solutions to the equation 6250=-0.1x^2+50x ?

The solutions to the equation 6250=-0.1x^2+50x are x=250

Find the zeros of 6250=-0.1x^2+50x

The zeros of 6250=-0.1x^2+50x are x=250

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6250 = - 0.1 x^{2} + 50 x

x = 250

Solution steps

6250 = - 0.1 x^{2} + 50 x

Multiply both sides by

10

62500 = - x^{2} + 500 x

Switch sides

- x^{2} + 500 x = 62500

Move

62500

to the left side

- x^{2} + 500 x - 62500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 500 \pm 50 0 ^{2} - 4 ( - 1 ) ( - 62500 )}{2 ( - 1 )}

50 0^{2} - 4 (- 1) (- 62500) = 0

x_{1, 2} = \frac{- 500 \pm 0}{2 ( - 1 )}

x = \frac{- 500}{2 ( - 1 )}

\frac{- 500}{2 ( - 1 )} = 250

x = 250

The solution to the quadratic equation is:

x = 250

\frac{2 x}{5} = \frac{x - 3}{4}

(3 x - 2)^{2}

(9^{\frac{1}{4}})^{\frac{7}{2}}

- 3 (- x + 4) = - 9

\frac{x}{7} = 2

What are the solutions to the equation 6250=-0.1x^2+50x ?
The solutions to the equation 6250=-0.1x^2+50x are x=250
Find the zeros of 6250=-0.1x^2+50x
The zeros of 6250=-0.1x^2+50x are x=250