What are the solutions to the equation 4x^2-4=0 ?

The solutions to the equation 4x^2-4=0 are x=1,x=-1

Find the zeros of 4x^2-4=0

The zeros of 4x^2-4=0 are x=1,x=-1

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4 x^{2} - 4 = 0

x = 1, x = - 1

Solution steps

4 x^{2} - 4 = 0

Move

4

to the right side

4 x^{2} = 4

Divide both sides by

4

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

n - 3.4 = - 12

- 8 - 2

36 x^{2} - 84 x + 49 - 64 y^{2}

3 x^{2} - 3 x - 60

0 < \frac{5}{x - 1} < 3

What are the solutions to the equation 4x^2-4=0 ?
The solutions to the equation 4x^2-4=0 are x=1,x=-1
Find the zeros of 4x^2-4=0
The zeros of 4x^2-4=0 are x=1,x=-1