What is the answer to a+((a-60)/3)+((a-10)/2)=180 ?

The answer to a+((a-60)/3)+((a-10)/2)=180 is a=(6*180+6*20+6*5)/(11)

Solve for a: a+((a-60)/3)+((a-10)/2)=180

The solution is a=(6*180+6*20+6*5)/(11)

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a + (\frac{a - 6 0 ^{\circ}}{3}) + (\frac{a - 1 0 ^{\circ}}{2}) = 18 0^{\circ}

a = \frac{6 \cdot 18 0 ^{\circ} + 6 \cdot 2 0 ^{\circ} + 6 \cdot 5 ^{\circ}}{11}

Decimal Notation

a = 1.95159 \dots

Solution steps

a + (\frac{a - 6 0 ^{\circ}}{3}) + (\frac{a - 1 0 ^{\circ}}{2}) = 18 0^{\circ}

Expand

a + (\frac{a - 6 0 ^{\circ}}{3}) + (\frac{a - 1 0 ^{\circ}}{2}) : \frac{11 a}{6} - 2 0^{\circ} - 5^{\circ}

\frac{11 a}{6} - 2 0^{\circ} - 5^{\circ} = 18 0^{\circ}

Multiply both sides by

6

11 a - 6 \cdot 2 0^{\circ} - 6 \cdot 5^{\circ} = 6 \cdot 18 0^{\circ}

Move

6 \cdot 2 0^{\circ}

to the right side

11 a - 6 \cdot 5^{\circ} = 6 \cdot 18 0^{\circ} + 6 \cdot 2 0^{\circ}

Move

6 \cdot 5^{\circ}

to the right side

11 a = 6 \cdot 18 0^{\circ} + 6 \cdot 2 0^{\circ} + 6 \cdot 5^{\circ}

Divide both sides by

11

a = \frac{6 \cdot 18 0 ^{\circ} + 6 \cdot 2 0 ^{\circ} + 6 \cdot 5 ^{\circ}}{11}

- 2 x^{2} + 7 x + 4

- 14 v + 6 v = 40

\frac{13 !}{( 13 - 6 ) !}

3 x - 3 = 0

∣ 2 x + 5 ∣ = 3 x + 4

What is the answer to a+((a-60)/3)+((a-10)/2)=180 ?
The answer to a+((a-60)/3)+((a-10)/2)=180 is a=(6*180+6*20+6*5)/(11)
Solve for a: a+((a-60)/3)+((a-10)/2)=180
The solution is a=(6*180+6*20+6*5)/(11)