What is factor 16a^4-81b^4 ?

The solution to factor 16a^4-81b^4 is (4a^2+9b^2)(2a+3b)(2a-3b)

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factor 16a^4-81b^4

factor

16 a^{4} - 81 b^{4}

(4 a^{2} + 9 b^{2}) (2 a + 3 b) (2 a - 3 b)

Solution steps

16 a^{4} - 81 b^{4}

16 a^{4} = (4 a^{2})^{2}

81 b^{4} = (9 b^{2})^{2}

= (4 a^{2})^{2} - (9 b^{2})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(4 a^{2})^{2} - (9 b^{2})^{2} = (4 a^{2} + 9 b^{2}) (4 a^{2} - 9 b^{2})

= (4 a^{2} + 9 b^{2}) (4 a^{2} - 9 b^{2})

Factor

4 a^{2} - 9 b^{2} : (2 a + 3 b) (2 a - 3 b)

= (4 a^{2} + 9 b^{2}) (2 a + 3 b) (2 a - 3 b)

(\frac{8 ^{- 5}}{2 ^{- 2}})^{- 4}

- \frac{13}{4} = \frac{3}{2} n + \frac{27}{8} n

- 12 x + 14 = - 34

3 lo g_{7} (4) + lo g_{7} (6)

\frac{1}{\frac{2}{1}}

What is factor 16a^4-81b^4 ?
The solution to factor 16a^4-81b^4 is (4a^2+9b^2)(2a+3b)(2a-3b)