What are the solutions to the equation (3x+2)^2=5 ?

The solutions to the equation (3x+2)^2=5 are x=(sqrt(5)-2)/3 ,x=(-sqrt(5)-2)/3

Find the zeros of (3x+2)^2=5

The zeros of (3x+2)^2=5 are x=(sqrt(5)-2)/3 ,x=(-sqrt(5)-2)/3

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(3 x + 2)^{2} = 5

x = \frac{5 - 2}{3}, x = \frac{- 5 - 2}{3}

Decimal Notation

x = 0.07868 \dots, x = - 1.41202 \dots

Solution steps

(3 x + 2)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 2 = 5 : x = \frac{5 - 2}{3}

Solve

3 x + 2 = - 5 : x = \frac{- 5 - 2}{3}

The solutions to the quadratic equation are:

x = \frac{5 - 2}{3}, x = \frac{- 5 - 2}{3}

\frac{( ( \frac{π}{2} ) ^{3} )}{3}

3 x^{3} - 6 x^{2}

∣ u + 7 ∣ \leq 3

\frac{x}{5} = - 2

What are the solutions to the equation (3x+2)^2=5 ?
The solutions to the equation (3x+2)^2=5 are x=(sqrt(5)-2)/3 ,x=(-sqrt(5)-2)/3
Find the zeros of (3x+2)^2=5
The zeros of (3x+2)^2=5 are x=(sqrt(5)-2)/3 ,x=(-sqrt(5)-2)/3