What is (5^{-8})(5^{-10}) ?

The solution to (5^{-8})(5^{-10}) is 1/(5^{18)}

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simplify (5^{-8})(5^{-10})

simplify

(5^{- 8}) (5^{- 10})

\frac{1}{5 ^{18}}

Decimal Notation

2.62144 E - 13

Solution steps

(5^{- 8}) (5^{- 10})

(5^{- 8}) (5^{- 10}) = 5^{- 8} \cdot 5^{- 10}

= 5^{- 8} \cdot 5^{- 10}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

5^{- 8} \cdot 5^{- 10} = 5^{- 8 - 10}

= 5^{- 8 - 10}

Subtract the numbers:

- 8 - 10 = - 18

= 5^{- 18}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

5^{- 18} = \frac{1}{5 ^{18}}

= \frac{1}{5 ^{18}}

(u^{\frac{1}{3}})^{\frac{4}{5}}

x - 3 > 5 or x + 3 < - 2

(x - 2)^{2} + 8 (x - 2) + 15

7 a - 5 a

\frac{3}{6} - \frac{1}{4}