What are the solutions to the equation 9^2+b^2=16^2 ?

The solutions to the equation 9^2+b^2=16^2 are b=5sqrt(7),b=-5sqrt(7)

Find the zeros of 9^2+b^2=16^2

The zeros of 9^2+b^2=16^2 are b=5sqrt(7),b=-5sqrt(7)

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9^{2} + b^{2} = 1 6^{2}

b = 57, b = - 57

Decimal Notation

b = 13.22875 \dots, b = - 13.22875 \dots

Solution steps

9^{2} + b^{2} = 1 6^{2}

Move

9^{2}

to the right side

b^{2} = 175

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 175, b = - 175

175 = 57

- 175 = - 57

b = 57, b = - 57

∣ x ∣ \geq 6

x + 8 < - 7

2 x \leq \frac{6 x - 8}{2} \leq \frac{14 x - 12}{2}

a^{2} + 4^{2} = 5^{2}

\frac{2 e ^{- s}}{5 s ^{2} + 45}

What are the solutions to the equation 9^2+b^2=16^2 ?
The solutions to the equation 9^2+b^2=16^2 are b=5sqrt(7),b=-5sqrt(7)
Find the zeros of 9^2+b^2=16^2
The zeros of 9^2+b^2=16^2 are b=5sqrt(7),b=-5sqrt(7)