en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n(3+n)=n^2+4n

Solution

n (3 + n) = n^{2} + 4 n

Solution

n = 0

Solution steps

n (3 + n) = n^{2} + 4 n

Expand

n (3 + n) : 3 n + n^{2}

3 n + n^{2} = n^{2} + 4 n

Subtract

n^{2} + 4 n

from both sides

3 n + n^{2} - (n^{2} + 4 n) = n^{2} + 4 n - (n^{2} + 4 n)

Simplify

- n = 0

Divide both sides by

- 1

n = 0

Popular Examples

3(4x-1)=7(2x-7)

3 (4 x - 1) = 7 (2 x - 7)

factor 12x^2+23x+5 factor

12 x^{2} + 23 x + 5

4 p^{2} = 12 p - 5

\frac{t}{- 2} < 6

factor x^3+8x^2-5x-40 factor

x^{3} + 8 x^{2} - 5 x - 40

Frequently Asked Questions (FAQ)

What is the answer to n(3+n)=n^2+4n ?
The answer to n(3+n)=n^2+4n is n=0
Solve for n: n(3+n)=n^2+4n
The solution is n=0