What are the solutions to the equation 2x^2-12x-26=0 ?

The solutions to the equation 2x^2-12x-26=0 are x=3+sqrt(22),x=3-sqrt(22)

Find the zeros of 2x^2-12x-26=0

The zeros of 2x^2-12x-26=0 are x=3+sqrt(22),x=3-sqrt(22)

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2 x^{2} - 12 x - 26 = 0

x = 3 + 22, x = 3 - 22

Decimal Notation

x = 7.69041 \dots, x = - 1.69041 \dots

Solution steps

2 x^{2} - 12 x - 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 ( - 26 )}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 (- 26) = 422

x_{1, 2} = \frac{- ( - 12 ) \pm 4 22}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 22}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 4 22}{2 \cdot 2}

x = \frac{- ( - 12 ) + 4 22}{2 \cdot 2} : 3 + 22

x = \frac{- ( - 12 ) - 4 22}{2 \cdot 2} : 3 - 22

The solutions to the quadratic equation are:

x = 3 + 22, x = 3 - 22

2 a^{2} + 16 a - 40

2 x^{2} - 8 x + 16

7 ∣ x + 2 ∣ + 5 > 4

(x + 2 i) (x - 2 i)

5 (6 + 3 r) + 7 \geq 127

What are the solutions to the equation 2x^2-12x-26=0 ?
The solutions to the equation 2x^2-12x-26=0 are x=3+sqrt(22),x=3-sqrt(22)
Find the zeros of 2x^2-12x-26=0
The zeros of 2x^2-12x-26=0 are x=3+sqrt(22),x=3-sqrt(22)