What are the solutions to the equation 50b^2+20b+2=0 ?

The solutions to the equation 50b^2+20b+2=0 are b=-1/5

Find the zeros of 50b^2+20b+2=0

The zeros of 50b^2+20b+2=0 are b=-1/5

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50 b^{2} + 20 b + 2 = 0

b = - \frac{1}{5}

Decimal Notation

b = - 0.2

Solution steps

50 b^{2} + 20 b + 2 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 50 \cdot 2}{2 \cdot 50}

2 0^{2} - 4 \cdot 50 \cdot 2 = 0

b_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 50}

b = \frac{- 20}{2 \cdot 50}

\frac{- 20}{2 \cdot 50} = - \frac{1}{5}

b = - \frac{1}{5}

The solution to the quadratic equation is:

b = - \frac{1}{5}

\frac{9 ^{4}}{9 ^{24}}

5 y^{2} - 2 y - 3

10 \leq z - 1 + 14

365

\frac{- 1}{1}

What are the solutions to the equation 50b^2+20b+2=0 ?
The solutions to the equation 50b^2+20b+2=0 are b=-1/5
Find the zeros of 50b^2+20b+2=0
The zeros of 50b^2+20b+2=0 are b=-1/5