What are the solutions to the equation (3t-6)^2-15(3t-6)+54=0 ?

The solutions to the equation (3t-6)^2-15(3t-6)+54=0 are t=5,t=4

Find the zeros of (3t-6)^2-15(3t-6)+54=0

The zeros of (3t-6)^2-15(3t-6)+54=0 are t=5,t=4

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(3 t - 6)^{2} - 15 (3 t - 6) + 54 = 0

t = 5, t = 4

Solution steps

(3 t - 6)^{2} - 15 (3 t - 6) + 54 = 0

Expand

(3 t - 6)^{2} - 15 (3 t - 6) + 54 : 9 t^{2} - 81 t + 180

9 t^{2} - 81 t + 180 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 81 ) \pm ( - 81 ) ^{2} - 4 \cdot 9 \cdot 180}{2 \cdot 9}

(- 81)^{2} - 4 \cdot 9 \cdot 180 = 9

t_{1, 2} = \frac{- ( - 81 ) \pm 9}{2 \cdot 9}

Separate the solutions

t_{1} = \frac{- ( - 81 ) + 9}{2 \cdot 9}, t_{2} = \frac{- ( - 81 ) - 9}{2 \cdot 9}

t = \frac{- ( - 81 ) + 9}{2 \cdot 9} : 5

t = \frac{- ( - 81 ) - 9}{2 \cdot 9} : 4

The solutions to the quadratic equation are:

t = 5, t = 4

6^{2} + 8^{2} = x^{2}

- 2 x - 7 \geq - 3

x^{2} \cdot 18 \cdot 1 0^{- 6} - x \cdot 0.024 \cdot 0.1 - \frac{1}{50 \cdot 1 0 ^{- 12}} = 0

- 4 y = 48

(\frac{1}{2})^{3}

What are the solutions to the equation (3t-6)^2-15(3t-6)+54=0 ?
The solutions to the equation (3t-6)^2-15(3t-6)+54=0 are t=5,t=4
Find the zeros of (3t-6)^2-15(3t-6)+54=0
The zeros of (3t-6)^2-15(3t-6)+54=0 are t=5,t=4