What is ((10x^3y^2)/(5x^{-3)y^4})^{-3} ?

The solution to ((10x^3y^2)/(5x^{-3)y^4})^{-3} is (y^6)/(8x^{18)}

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simplify ((10x^3y^2)/(5x^{-3)y^4})^{-3}

simplify

(\frac{10 x ^{3} y ^{2}}{5 x ^{- 3} y ^{4}})^{- 3}

\frac{y ^{6}}{8 x ^{18}}

Solution steps

(\frac{10 x ^{3} y ^{2}}{5 x ^{- 3} y ^{4}})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{10 x ^{3} y ^{2}}{5 x ^{- 3} y ^{4}})^{- 3} = \frac{1}{( \frac{10 x ^{3} y ^{2}}{5 x ^{- 3} y ^{4}} ) ^{3}}

= \frac{1}{( \frac{10 x ^{3} y ^{2}}{5 x ^{- 3} y ^{4}} ) ^{3}}

Simplify

(\frac{10 x ^{3} y ^{2}}{5 x ^{- 3} y ^{4}})^{3} : \frac{8 x ^{18}}{y ^{6}}

= \frac{1}{\frac{8 x ^{18}}{y ^{6}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{y ^{6}}{8 x ^{18}}

2 x + 4 < 6

- \frac{8}{2 i}

- 2 x^{2} - 4 x + 16 = 0

x + 2 = x + 5

12 x + 36 < 324

What is ((10x^3y^2)/(5x^{-3)y^4})^{-3} ?
The solution to ((10x^3y^2)/(5x^{-3)y^4})^{-3} is (y^6)/(8x^{18)}