What are the solutions to the equation 2x^2+6x-3=0 ?

The solutions to the equation 2x^2+6x-3=0 are x=(-3+sqrt(15))/2 ,x=-(3+sqrt(15))/2

Find the zeros of 2x^2+6x-3=0

The zeros of 2x^2+6x-3=0 are x=(-3+sqrt(15))/2 ,x=-(3+sqrt(15))/2

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2 x^{2} + 6 x - 3 = 0

x = \frac{- 3 + 15}{2}, x = - \frac{3 + 15}{2}

Decimal Notation

x = 0.43649 \dots, x = - 3.43649 \dots

Solution steps

2 x^{2} + 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 3) = 215

x_{1, 2} = \frac{- 6 \pm 2 15}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 2 15}{2 \cdot 2}, x_{2} = \frac{- 6 - 2 15}{2 \cdot 2}

x = \frac{- 6 + 2 15}{2 \cdot 2} : \frac{- 3 + 15}{2}

x = \frac{- 6 - 2 15}{2 \cdot 2} : - \frac{3 + 15}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 15}{2}, x = - \frac{3 + 15}{2}

(x^{2})^{3}

\frac{2 π}{\frac{7}{3}}

5 x^{2} = 2 x

a^{2} + 1 2^{2} = 1 5^{2}

- 3 \leq x - 2 < 5

What are the solutions to the equation 2x^2+6x-3=0 ?
The solutions to the equation 2x^2+6x-3=0 are x=(-3+sqrt(15))/2 ,x=-(3+sqrt(15))/2
Find the zeros of 2x^2+6x-3=0
The zeros of 2x^2+6x-3=0 are x=(-3+sqrt(15))/2 ,x=-(3+sqrt(15))/2