What are the solutions to the equation (x-4)^2=5 ?

The solutions to the equation (x-4)^2=5 are x=sqrt(5)+4,x=-sqrt(5)+4

Find the zeros of (x-4)^2=5

The zeros of (x-4)^2=5 are x=sqrt(5)+4,x=-sqrt(5)+4

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(x - 4)^{2} = 5

x = 5 + 4, x = - 5 + 4

Decimal Notation

x = 6.23606 \dots, x = 1.76393 \dots

Solution steps

(x - 4)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 5 : x = 5 + 4

Solve

x - 4 = - 5 : x = - 5 + 4

The solutions to the quadratic equation are:

x = 5 + 4, x = - 5 + 4

17 x y^{4} + 51 x^{3} y^{3}

12 x^{2} - 12 x = 0

2 (3 t - 1) - 5 t > - 6 (1 - t) + 7

8 x + 47 = 8 (x + 5)

∣ 2 x + 3 ∣ < 3

What are the solutions to the equation (x-4)^2=5 ?
The solutions to the equation (x-4)^2=5 are x=sqrt(5)+4,x=-sqrt(5)+4
Find the zeros of (x-4)^2=5
The zeros of (x-4)^2=5 are x=sqrt(5)+4,x=-sqrt(5)+4