What is 3/(2x+3)< 1/(x-2) ?

The solution to 3/(2x+3)< 1/(x-2) is x<-3/2 \lor 2<x<9

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3/(2x+3)< 1/(x-2)

\frac{3}{2 x + 3} < \frac{1}{x - 2}

x < - \frac{3}{2} or 2 < x < 9

Interval Notation

(- \infty, - \frac{3}{2}) \cup (2, 9)

Decimal Notation

x < - 1.5 or 2 < x < 9

Solution steps

\frac{3}{2 x + 3} < \frac{1}{x - 2}

Rewrite in standard form

\frac{x - 9}{( x - 2 ) ( 2 x + 3 )} < 0

Identify the intervals

x < - \frac{3}{2} or 2 < x < 9

(3 x^{3})^{3}

x^{2} + 5 x + 36 = 0

3 + 4 x + 5 x = 21

x^{2} - 6 = ∣ x ∣

5 x^{2} - 15 x - 10 = 0

What is 3/(2x+3)< 1/(x-2) ?
The solution to 3/(2x+3)< 1/(x-2) is x<-3/2 \lor 2<x<9