What is the answer to 4x(3x-2)-5x(2x-4)=2x^2+7 ?

The answer to 4x(3x-2)-5x(2x-4)=2x^2+7 is x= 7/12

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4x(3x-2)-5x(2x-4)=2x^2+7

4 x (3 x - 2) - 5 x (2 x - 4) = 2 x^{2} + 7

x = \frac{7}{12}

Decimal Notation

x = 0.58333 \dots

Solution steps

4 x (3 x - 2) - 5 x (2 x - 4) = 2 x^{2} + 7

Expand

4 x (3 x - 2) - 5 x (2 x - 4) : 2 x^{2} + 12 x

2 x^{2} + 12 x = 2 x^{2} + 7

Move

2 x^{2}

to the left side

12 x = 7

Divide both sides by

12

x = \frac{7}{12}

- 7 x + 10 = x^{2}

- 5 x^{2} - 9 x = 0

2 x^{2} - 5 x + 11 = 0

y + 6 < 10 or 2 y - 3 > 9

- 2 x^{4} + 13 x^{3} - 21 x^{2} + 2 x + 8

What is the answer to 4x(3x-2)-5x(2x-4)=2x^2+7 ?
The answer to 4x(3x-2)-5x(2x-4)=2x^2+7 is x= 7/12
Solve for x: 4x(3x-2)-5x(2x-4)=2x^2+7
The solution is x= 7/12