What are the solutions to the equation 12x=4x^2+9 ?

The solutions to the equation 12x=4x^2+9 are x= 3/2

Find the zeros of 12x=4x^2+9

The zeros of 12x=4x^2+9 are x= 3/2

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12 x = 4 x^{2} + 9

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

12 x = 4 x^{2} + 9

Switch sides

4 x^{2} + 9 = 12 x

Move

12 x

to the left side

4 x^{2} + 9 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 12 )}{2 \cdot 4}

\frac{- ( - 12 )}{2 \cdot 4} = \frac{3}{2}

x = \frac{3}{2}

The solution to the quadratic equation is:

x = \frac{3}{2}

\frac{16}{35} \cdot \frac{25}{48}

2 b + 10 \geq - 7 b - 2

x^{2} + 10 x y - 171 y^{2}

i^{27}

2 x^{2} - 6 x - 10 = 0

What are the solutions to the equation 12x=4x^2+9 ?
The solutions to the equation 12x=4x^2+9 are x= 3/2
Find the zeros of 12x=4x^2+9
The zeros of 12x=4x^2+9 are x= 3/2