What are the solutions to the equation 25^2=x^2+15^2 ?

The solutions to the equation 25^2=x^2+15^2 are x=20,x=-20

Find the zeros of 25^2=x^2+15^2

The zeros of 25^2=x^2+15^2 are x=20,x=-20

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2 5^{2} = x^{2} + 1 5^{2}

x = 20, x = - 20

Solution steps

2 5^{2} = x^{2} + 1 5^{2}

Switch sides

x^{2} + 1 5^{2} = 2 5^{2}

Move

1 5^{2}

to the right side

x^{2} = 400

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 400, x = - 400

400 = 20

- 400 = - 20

x = 20, x = - 20

4 m^{2} - 4 m - 63

∣ 5 x - 7 ∣ + 7 = 6

27 ab - 9 b^{2} - 20 a^{2}

∣ p + 4 ∣ \leq 8

\frac{\frac{1}{2}}{4}

What are the solutions to the equation 25^2=x^2+15^2 ?
The solutions to the equation 25^2=x^2+15^2 are x=20,x=-20
Find the zeros of 25^2=x^2+15^2
The zeros of 25^2=x^2+15^2 are x=20,x=-20