What are the solutions to the equation x^2-2/3 x-1/3-(-2/6)=0 ?

The solutions to the equation x^2-2/3 x-1/3-(-2/6)=0 are x= 2/3 ,x=0

Find the zeros of x^2-2/3 x-1/3-(-2/6)=0

The zeros of x^2-2/3 x-1/3-(-2/6)=0 are x= 2/3 ,x=0

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x^{2} - \frac{2}{3} x - \frac{1}{3} - (- \frac{2}{6}) = 0

x = \frac{2}{3}, x = 0

Decimal Notation

x = 0.66666 \dots, x = 0

Solution steps

x^{2} - \frac{2}{3} x - \frac{1}{3} - (- \frac{2}{6}) = 0

Multiply both sides by

3

3 x^{2} - 2 x - 1 + 1 = 0

3 x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2}{2 \cdot 3} : \frac{2}{3}

x = \frac{- ( - 2 ) - 2}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = 0

16 = \frac{1}{2} b

x^{2} + 12 x + 30 = 0

3 (- 2)^{4}

12 - 3 f = 7

\frac{7}{4} (2)

What are the solutions to the equation x^2-2/3 x-1/3-(-2/6)=0 ?
The solutions to the equation x^2-2/3 x-1/3-(-2/6)=0 are x= 2/3 ,x=0
Find the zeros of x^2-2/3 x-1/3-(-2/6)=0
The zeros of x^2-2/3 x-1/3-(-2/6)=0 are x= 2/3 ,x=0