What are the solutions to the equation x^2-7x+7=0 ?

The solutions to the equation x^2-7x+7=0 are x=(7+sqrt(21))/2 ,x=(7-sqrt(21))/2

Find the zeros of x^2-7x+7=0

The zeros of x^2-7x+7=0 are x=(7+sqrt(21))/2 ,x=(7-sqrt(21))/2

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x^{2} - 7 x + 7 = 0

x = \frac{7 + 21}{2}, x = \frac{7 - 21}{2}

Decimal Notation

x = 5.79128 \dots, x = 1.20871 \dots

Solution steps

x^{2} - 7 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 7 = 21

x_{1, 2} = \frac{- ( - 7 ) \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 21}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 21}{2 \cdot 1}

x = \frac{- ( - 7 ) + 21}{2 \cdot 1} : \frac{7 + 21}{2}

x = \frac{- ( - 7 ) - 21}{2 \cdot 1} : \frac{7 - 21}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 21}{2}, x = \frac{7 - 21}{2}

\frac{8 !}{2 !}

(x - 5) (x + 5) = 0

12 x^{4} + 2 x^{3} - 30 x - 5

2 x^{2} - 8 \leq 0

2 x^{2} - 10 x - 48

What are the solutions to the equation x^2-7x+7=0 ?
The solutions to the equation x^2-7x+7=0 are x=(7+sqrt(21))/2 ,x=(7-sqrt(21))/2
Find the zeros of x^2-7x+7=0
The zeros of x^2-7x+7=0 are x=(7+sqrt(21))/2 ,x=(7-sqrt(21))/2