What are the solutions to the equation 6x^2-23x+7=0 ?

The solutions to the equation 6x^2-23x+7=0 are x= 7/2 ,x= 1/3

Find the zeros of 6x^2-23x+7=0

The zeros of 6x^2-23x+7=0 are x= 7/2 ,x= 1/3

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6 x^{2} - 23 x + 7 = 0

x = \frac{7}{2}, x = \frac{1}{3}

Decimal Notation

x = 3.5, x = 0.33333 \dots

Solution steps

6 x^{2} - 23 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 6 \cdot 7}{2 \cdot 6}

(- 23)^{2} - 4 \cdot 6 \cdot 7 = 19

x_{1, 2} = \frac{- ( - 23 ) \pm 19}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 23 ) + 19}{2 \cdot 6}, x_{2} = \frac{- ( - 23 ) - 19}{2 \cdot 6}

x = \frac{- ( - 23 ) + 19}{2 \cdot 6} : \frac{7}{2}

x = \frac{- ( - 23 ) - 19}{2 \cdot 6} : \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = \frac{1}{3}

x^{3} + 6 x^{2} + 11 x + 6

- 3 s > 33

8 - 3 x \geq 5

w^{2} + 7 w + 12

What are the solutions to the equation 6x^2-23x+7=0 ?
The solutions to the equation 6x^2-23x+7=0 are x= 7/2 ,x= 1/3
Find the zeros of 6x^2-23x+7=0
The zeros of 6x^2-23x+7=0 are x= 7/2 ,x= 1/3