What are the solutions to the equation y^2-10y-24=0 ?

The solutions to the equation y^2-10y-24=0 are y=12,y=-2

Find the zeros of y^2-10y-24=0

The zeros of y^2-10y-24=0 are y=12,y=-2

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y^{2} - 10 y - 24 = 0

y = 12, y = - 2

Solution steps

y^{2} - 10 y - 24 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 24) = 14

y_{1, 2} = \frac{- ( - 10 ) \pm 14}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 10 ) + 14}{2 \cdot 1}, y_{2} = \frac{- ( - 10 ) - 14}{2 \cdot 1}

y = \frac{- ( - 10 ) + 14}{2 \cdot 1} : 12

y = \frac{- ( - 10 ) - 14}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

y = 12, y = - 2

x + (- 27) = 0

4 = \frac{2}{9} x

27 v^{3} + 64

11 + 7 x \geq 25

What are the solutions to the equation y^2-10y-24=0 ?
The solutions to the equation y^2-10y-24=0 are y=12,y=-2
Find the zeros of y^2-10y-24=0
The zeros of y^2-10y-24=0 are y=12,y=-2