What are the solutions to the equation x^2-12x+35=0 ?

The solutions to the equation x^2-12x+35=0 are x=7,x=5

Find the zeros of x^2-12x+35=0

The zeros of x^2-12x+35=0 are x=7,x=5

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x^{2} - 12 x + 35 = 0

x = 7, x = 5

Solution steps

x^{2} - 12 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 35 = 2

x_{1, 2} = \frac{- ( - 12 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2}{2 \cdot 1} : 7

x = \frac{- ( - 12 ) - 2}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

x = 7, x = 5

16 (\frac{88 - 16 B}{52}) + 6 B - 30 = 0

2 w + 9 = 7 w^{2}

3 x^{2} - 150 = 282

14 x^{2} - 33 x y + 13 y^{2}

f = \frac{( 29 - 2 )}{3}

What are the solutions to the equation x^2-12x+35=0 ?
The solutions to the equation x^2-12x+35=0 are x=7,x=5
Find the zeros of x^2-12x+35=0
The zeros of x^2-12x+35=0 are x=7,x=5