What are the solutions to the equation (x^2)/2+7/2 x=1 ?

The solutions to the equation (x^2)/2+7/2 x=1 are x=(-7+sqrt(57))/2 ,x=(-7-sqrt(57))/2

Find the zeros of (x^2)/2+7/2 x=1

The zeros of (x^2)/2+7/2 x=1 are x=(-7+sqrt(57))/2 ,x=(-7-sqrt(57))/2

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\frac{x ^{2}}{2} + \frac{7}{2} x = 1

x = \frac{- 7 + 57}{2}, x = \frac{- 7 - 57}{2}

Decimal Notation

x = 0.27491 \dots, x = - 7.27491 \dots

Solution steps

\frac{x ^{2}}{2} + \frac{7}{2} x = 1

Multiply both sides by

2

x^{2} + 7 x = 2

Move

2

to the left side

x^{2} + 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 2) = 57

x_{1, 2} = \frac{- 7 \pm 57}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 57}{2 \cdot 1}, x_{2} = \frac{- 7 - 57}{2 \cdot 1}

x = \frac{- 7 + 57}{2 \cdot 1} : \frac{- 7 + 57}{2}

x = \frac{- 7 - 57}{2 \cdot 1} : \frac{- 7 - 57}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 57}{2}, x = \frac{- 7 - 57}{2}

2 (z - 10) = - 4

5 x + 8 \geq - 37

7 x + 2 (2 x + 18) = 6 - 4 x

2 x = - 14

\frac{1}{\frac{2}{3}}

What are the solutions to the equation (x^2)/2+7/2 x=1 ?
The solutions to the equation (x^2)/2+7/2 x=1 are x=(-7+sqrt(57))/2 ,x=(-7-sqrt(57))/2
Find the zeros of (x^2)/2+7/2 x=1
The zeros of (x^2)/2+7/2 x=1 are x=(-7+sqrt(57))/2 ,x=(-7-sqrt(57))/2