What are the solutions to the equation x^2+5x-14=0 ?

The solutions to the equation x^2+5x-14=0 are x=2,x=-7

Find the zeros of x^2+5x-14=0

The zeros of x^2+5x-14=0 are x=2,x=-7

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x^{2} + 5 x - 14 = 0

x = 2, x = - 7

Solution steps

x^{2} + 5 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 14) = 9

x_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 9}{2 \cdot 1}, x_{2} = \frac{- 5 - 9}{2 \cdot 1}

x = \frac{- 5 + 9}{2 \cdot 1} : 2

x = \frac{- 5 - 9}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 2, x = - 7

2 m - m^{2}

343 z^{3} + 27 x^{3}

5 x^{2} - 21 x - 20

5 v^{2} - 30 v + 40

20 x^{2} y - 28 x

What are the solutions to the equation x^2+5x-14=0 ?
The solutions to the equation x^2+5x-14=0 are x=2,x=-7
Find the zeros of x^2+5x-14=0
The zeros of x^2+5x-14=0 are x=2,x=-7