What is (x^2-x-2)/(x^2+x-2)>= 0 ?

The solution to (x^2-x-2)/(x^2+x-2)>= 0 is x = 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2-x-2)/(x^2+x-2)>= 0

\frac{x ^{2} - x - 2}{x ^{2} + x - 2} \geq 0

x < - 2 or - 1 \leq x < 1 or x \geq 2

Interval Notation

(- \infty, - 2) \cup [- 1, 1) \cup [2, \infty)

Solution steps

\frac{x ^{2} - x - 2}{x ^{2} + x - 2} \geq 0

Factor

\frac{x ^{2} - x - 2}{x ^{2} + x - 2} : \frac{( x + 1 ) ( x - 2 )}{( x - 1 ) ( x + 2 )}

\frac{( x + 1 ) ( x - 2 )}{( x - 1 ) ( x + 2 )} \geq 0

Identify the intervals

x < - 2 or - 1 \leq x < 1 or x \geq 2

9 x^{3} - 7 x + 2

\frac{9}{7} - \frac{5}{7} + (\frac{3}{7} - \frac{1}{7}) + \frac{3}{7}

x^{4} - 3 x^{2} + 4 x + 15 = 0

- 2 - \frac{7 a}{- 4} \leq - 7

(4) (918)

What is (x^2-x-2)/(x^2+x-2)>= 0 ?
The solution to (x^2-x-2)/(x^2+x-2)>= 0 is x<-2\lor-1<= x<1\lor x>= 2