What are the solutions to the equation 2x(x-3)=4+x ?

The solutions to the equation 2x(x-3)=4+x are x=4,x=-1/2

Find the zeros of 2x(x-3)=4+x

The zeros of 2x(x-3)=4+x are x=4,x=-1/2

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2 x (x - 3) = 4 + x

x = 4, x = - \frac{1}{2}

Decimal Notation

x = 4, x = - 0.5

Solution steps

2 x (x - 3) = 4 + x

Expand

2 x (x - 3) : 2 x^{2} - 6 x

2 x^{2} - 6 x = 4 + x

Move

x

to the left side

2 x^{2} - 7 x = 4

Move

4

to the left side

2 x^{2} - 7 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 4) = 9

x_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 2}

x = \frac{- ( - 7 ) + 9}{2 \cdot 2} : 4

x = \frac{- ( - 7 ) - 9}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 4, x = - \frac{1}{2}

3 x^{2} - 11 x = 4

3 x^{2} - 11 x + 10 = 0

- \frac{1}{3} q + \frac{1}{2} = - \frac{5}{6}

x - 2 - 3 x = - 4 x + 2

- 3 x > - 6

What are the solutions to the equation 2x(x-3)=4+x ?
The solutions to the equation 2x(x-3)=4+x are x=4,x=-1/2
Find the zeros of 2x(x-3)=4+x
The zeros of 2x(x-3)=4+x are x=4,x=-1/2