What are the solutions to the equation 2r^2+19r-10=0 ?

The solutions to the equation 2r^2+19r-10=0 are r= 1/2 ,r=-10

Find the zeros of 2r^2+19r-10=0

The zeros of 2r^2+19r-10=0 are r= 1/2 ,r=-10

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2 r^{2} + 19 r - 10 = 0

r = \frac{1}{2}, r = - 10

Decimal Notation

r = 0.5, r = - 10

Solution steps

2 r^{2} + 19 r - 10 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

1 9^{2} - 4 \cdot 2 (- 10) = 21

r_{1, 2} = \frac{- 19 \pm 21}{2 \cdot 2}

Separate the solutions

r_{1} = \frac{- 19 + 21}{2 \cdot 2}, r_{2} = \frac{- 19 - 21}{2 \cdot 2}

r = \frac{- 19 + 21}{2 \cdot 2} : \frac{1}{2}

r = \frac{- 19 - 21}{2 \cdot 2} : - 10

The solutions to the quadratic equation are:

r = \frac{1}{2}, r = - 10

- a - 5 (8 a - 1) = 39 - 7 a

- 4 x + 6 x^{2} = - 4 + 3 x^{2}

(43)^{2}

5 ∣ 2 x + 1 ∣ - 3 \leq 7

2 x + 3 \leq 7

What are the solutions to the equation 2r^2+19r-10=0 ?
The solutions to the equation 2r^2+19r-10=0 are r= 1/2 ,r=-10
Find the zeros of 2r^2+19r-10=0
The zeros of 2r^2+19r-10=0 are r= 1/2 ,r=-10