What are the solutions to the equation x^2+3x-4=0 ?

The solutions to the equation x^2+3x-4=0 are x=1,x=-4

Find the zeros of x^2+3x-4=0

The zeros of x^2+3x-4=0 are x=1,x=-4

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x^{2} + 3 x - 4 = 0

x = 1, x = - 4

Solution steps

x^{2} + 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 4) = 5

x_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 5}{2 \cdot 1}, x_{2} = \frac{- 3 - 5}{2 \cdot 1}

x = \frac{- 3 + 5}{2 \cdot 1} : 1

x = \frac{- 3 - 5}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 1, x = - 4

∣ 6 ∣

- 30 = 5 (x + 1)

a (x^{3} + 1) + 3 a x (x + 1)

25 x^{2} - 16 = 0

\frac{1}{a - b} - \frac{1}{b - a}

What are the solutions to the equation x^2+3x-4=0 ?
The solutions to the equation x^2+3x-4=0 are x=1,x=-4
Find the zeros of x^2+3x-4=0
The zeros of x^2+3x-4=0 are x=1,x=-4