What are the solutions to the equation 8=x^2-2x ?

The solutions to the equation 8=x^2-2x are x=4,x=-2

Find the zeros of 8=x^2-2x

The zeros of 8=x^2-2x are x=4,x=-2

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8 = x^{2} - 2 x

x = 4, x = - 2

Solution steps

8 = x^{2} - 2 x

Switch sides

x^{2} - 2 x = 8

Move

8

to the left side

x^{2} - 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 8) = 6

x_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 1}

x = \frac{- ( - 2 ) + 6}{2 \cdot 1} : 4

x = \frac{- ( - 2 ) - 6}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 4, x = - 2

- \frac{x}{4} + 2 > 11

6 - 2 y + 1 < 3

f (x) = (\frac{1}{2})^{x + 3}

\frac{1}{4} \times \frac{1}{4}

What are the solutions to the equation 8=x^2-2x ?
The solutions to the equation 8=x^2-2x are x=4,x=-2
Find the zeros of 8=x^2-2x
The zeros of 8=x^2-2x are x=4,x=-2